please helpfind the perimeter of the polygon with the verdices u(-2,4),v(3,4) and w(3,-4) round to the nearest hundredththe perimeter is about _______ units​

Answer:22.43 unitsStep-by-step explanation:we know thatThe perimeter of a polygon is the sum of its length sidesthe formula to calculate the distance between two points is equal to [tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex] we haveu(-2,4),v(3,4) and w(3,-4)step 1 Find the distance uvsubstitute the values[tex]d=\sqrt{(4-4)^{2}+(3+2)^{2}}[/tex] [tex]d=\sqrt{(0)^{2}+(5)^{2}}[/tex] [tex]uv=5\ units[/tex] step 2Find the distance vwsubstitute the values[tex]d=\sqrt{(-4-4)^{2}+(3-3)^{2}}[/tex] [tex]d=\sqrt{(-8)^{2}+(0)^{2}}[/tex] [tex]vw=8\ units[/tex] step 3Find the distance uwsubstitute the values[tex]d=\sqrt{(-4-4)^{2}+(3+2)^{2}}[/tex] [tex]d=\sqrt{(-8)^{2}+(5)^{2}}[/tex] [tex]uw=\sqrt{89}=9.43\ units[/tex] step 4 Find the perimeter[tex]P=uv+vw+uw=5+8+9.43=22.43\ units[/tex]