Kathy bicycles 8km/h faster than Dennis. In my he same time it takes Dennis to bicycle 36 km, Kathy can bicycle 60 km. How fast does each bicyclist travel

Dennis = 12 km'hKathy = 20 km/hStep-by-step explanation:Lets first establish  that time is the same for both Kathy and Dennis and we can therefore assign is the value of tKathy is cycling 8km/h faster than Dennis. Therefore if Dennis is doing x km/h Kathy is doing (x+8)km/hIf it takes Kathy t time to cycle for 60 km at (x+8)km/h, we can derive the time t as;(x+8)* t = 60 t = 60/(x+8)We can now use this time to establsish how fast Dennis is cycling. Dennis, using a speed of x km/h takes the same time (60/(x+8)) to cycle for 36 km. Therefore;x * 60/(x+8) = 36= 60x/(x+8) = 36 36 (x + 8) = 60x36x + 288 = 60x288 = 60x – 36x 288 = 24x 12 = x Dennis is cycling at 12 km/hKathy is doing x + 8 = 12 + 8 = 20 km/hLearn More:For more on deriving equations check out;